ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() in Python
Dung Do Tien
Aug 23 2021
195
Hi Guys, I have an array in Python 3.8.2 and I want to check all items of it.
If the item is odd number -> return false and it's even number -> return true:
import numpy as np
ageData = [12, 15, 19, 24, 27, 35, 46, 58, 63, 78, 81]
ageArray = np.array(ageData)
print(bool(ageArray % 2))
I want to return from
[12, 15, 19, 24, 27, 35, 46, 58, 63, 78, 81]
to
[true, false, false, true, false, false, true, true, false, true, false]
But when I run code I get an error ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
Traceback (most recent call last):
File "main.py", line 5, in <module>
print(bool(ageArray % 2))
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
Pls help me what is it? and how can I resolve it?
Thanks!
Have 1 answer(s) found.
-
J1
Jose Luis Aug 23 2021
You can not use
bool()
method to help convert true/false conditions. You can see code bellow:import numpy as np ageData = [12, 15, 19, 24, 27, 35, 46, 58, 63, 78, 81] ageArray = np.array(ageData) boolArr = (ageArray % 2) <= 0 print(boolArr)
#Output
[True False False True False False True True False True False]
It's so easy!! I hope it helpful to you.
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