# Error divide by zero encountered in double_scalars in Python

Dung Do Tien Dec 03 2021 673

Hello guys, I'm newbie in Python and I created a short function help caculate float number for me, you can see as below:

``````import numpy as np

def float_number(x):
x = np.float_(x)
y = int(input("Input large number: "))
return 10.7 / (5. - x)

print ('Float function with value 5 = ', odd_even(5.))``````

I use float_ fuction of numpy package to help convert number integer to float, but when run app it throw an exception main.py:6: RuntimeWarning: divide by zero encountered in double_scalars.

``````Input large number: 12
main.py:6: RuntimeWarning: divide by zero encountered in double_scalars
return 10.7 / (5. - x)
Float function with value 5 =  inf``````

I understand that 10.7 / 0 with throw exception, but I really don't know any solution to solve it.

I'm using Python 3.9 and window 10.

Thankyou for any solution for me.

• A

Alexis Nidegger Dec 03 2021

You can check parameter before calculate and return data. You can check if x value equal 5 will return 0;

See example below:

``````import numpy as np

def float_number(x):
if x == 5:
return 0;
x = np.float_(x)
y = int(input("Input large number: "))
return 10.7 / (5. - x)

print ('Float function with value 5 = ', float_number(6.))``````

#Output

``Float function with value 5 =  0``

I hope it is a best solution for you.

• D

Deepak M Dec 03 2021

You need check value input before divide, as below:

``````def float_number(x):
if (5. - x) == 0:
return 0;
x = np.float_(x)
y = int(input("Input large number: "))
return 10.7 / (5. - x)``````

And it fixed for you, exception will not throw again.