TypeError: unsupported operand type(s) for +: 'int' and 'str' in Python
Hello you guys, I am a newbie in Python and I'm also studying more about Python.
I have some lines of code and I want to create an array and remove any item from thay array. Function as below:
you = int(input("Enter your age: "))
mother = int(input("Enter your mother age: "))
father = int(input("Enter your father age: "))
wife = int(input("Enter your wife age: "))
lstage = [you, mother, father, wife]
print(lstage)
print("Now I will remove you father age....")
print(lstage.pop(2) + " has been removed")
print("And the list ages looks like: " + str(lstage))
But I get an exception TypeError: unsupported operand type(s) for +: 'int' and 'str' when I run code above.
Enter your age: 34
Enter your mother age: 56
Enter your father age: 65
Enter your wife age: 32
[34, 56, 65, 32]
Now I will remove you father age....
Traceback (most recent call last):
File "main.py", line 9, in <module>
print(lstage.pop(2) + " has been removed")
TypeError: unsupported operand type(s) for +: 'int' and 'str'
And I am using python 3.8.2
Anyone can explain it to me? How can I solve it?
Thanks for any suggestions.
-
N0
Nitin Kumar Oct 04 2021
Your code has some problem.
1. In line 9
lstage.pop(2)
is not return string so you have to cast it to string data type by usingstr()
method. See like:print(str(lstage.pop(2)) + " has been removed")
2. When concat string, please use
,
instate of+
sign.Change:
print(str(lstage.pop(2)) + " has been removed") print("And the list ages looks like: " + str(lstage))
To
print(str(lstage.pop(2)), " has been removed") print("And the list ages looks like: ", str(lstage))
And it worked for you.
-
k0
kolade afeez Oct 04 2021
You need to change line:
print(lstage.pop(2) + " has been removed")
To
rmitem = str(lstage.pop(2)) print(rmitem, " has been removed")
Because you need to convert
lstage.pop(2)
to string before concating them.
* Type maximum 2000 characters.
* All comments have to wait approved before display.
* Please polite comment and respect questions and answers of others.