TypeError: 'float' object cannot be interpreted as an integer in Python
Dung Do Tien
Sep 05 2021
179
Hello you guys, I am a newbie in Python and I'm also studying more about Python.
I have a small assignment, I want to loop and print a range of numbers. Like this:
for i in range( 2.1, 5 ):
print( i )
My code needs to be printed:
2.10000 2.20000 2.30000 ....
But I get an exception TypeError: 'float' object cannot be interpreted as an integer when I run the code above.
Traceback (most recent call last):
File "main.py", line 1, in <module>
for i in range(3.3, 5 ):
TypeError: 'float' object cannot be interpreted as an integer
And I am using python 3.8.2
Anyone can explain it to me? How can I solve it?
Thanks for any response.
Have 1 answer(s) found.
-
N0
Nguyễn Hồng Quân Sep 05 2021
The
range()method only works with integers, not floats. But you can create your own range generator that will do what you want:def frange(start, stop, step=1): i = start while i < stop: yield i i += stepfor i in frange(3.3, 5)will give you the output you want.Note, however, that
frangeunlikerange, it will return a generator, not a list.
* Type maximum 2000 characters.
* All comments have to wait approved before display.
* Please polite comment and respect questions and answers of others.