TypeError: 'float' object cannot be interpreted as an integer in Python

Dung Do Tien Sep 05 2021 41

Hello you guys, I am a newbie in Python and I'm also studying more about Python.
I have a small assignment, I want to loop and print a range of numbers. Like this:

 for i in range( 2.1, 5 ):
        print( i )

My code needs to be printed:

 2.10000 2.20000 2.30000 ....

But I get an exception TypeError: 'float' object cannot be interpreted as an integer when I run the code above.

 Traceback (most recent call last):
  File "main.py", line 1, in <module>
    for i in range(3.3, 5 ):
TypeError: 'float' object cannot be interpreted as an integer

And I am using python 3.8.2

Anyone can explain it to me? How can I solve it?

Thanks for any response.

Have 1 answer(s) found.
  • N

    Nguyễn Hồng Quân Sep 05 2021

    The range() method only works with integers, not floats. But you can create your own range generator that will do what you want:

     def frange(start, stop, step=1):
        i = start
        while i < stop:
            yield i
            i += step 

    for i in frange(3.3, 5) will give you the output you want.

    Note, however, that frange unlike range, it will return a generator, not a list.

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