Throw TypeError: 'int' object is not iterable in Python

Dung Do Tien Oct 07 2021 124

Hello you guys, I am a newbie in Python and I'm also studying more about Python.

I have some lines of code I want to find text and count time it found. I code function as below:

def find_word(intput, textsearch):
    found = 0
    for i in len(intput):
        if intput[i] == textsearch:
           found = found + 1
    return found

intcount = find_word("I'm learning python" , "n")
print(intcount)

But I get an exception throw TypeError: 'int' object is not iterable when I run code above.

Traceback (most recent call last):
  File "main.py", line 8, in <module>
    intcount = find_word("I'm learning python" , "n")
  File "main.py", line 3, in find_word
    for i in len(intput):
TypeError: 'int' object is not iterable

And I am using python 3.8.2

Anyone can explain it to me? How can I solve it?

Thanks for any suggestions.

Have 2 answer(s) found.
  • M

    Mobile Legend Oct 07 2021

    You can try run command

    print(len(intput))

    You can see it print out 19 and it is a number and not is iterable.

    So to fix this issue you can use range method to help interable with for loop. See code below (line 3):

    def find_word(intput, textsearch):
    found = 0
    for i in range(len(intput)):
        if intput[i] == textsearch:
            found = found + 1
    return found

intcount = find_word("I'm learning python" , "n")
print(intcount)

    #Output is 3

    I hope it helpful for you.

  • M

    Minh Phan Oct 07 2021

    Change: 

    for i in len(intput):

    to

    for i in range(len(intput)):

    And it will be solved for you.

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