Throw typeerror: 'float' object is not iterable in Python
Dung Do Tien
Oct 19 2021
164
Hello you guys, I a newbie in Python and I'm also studying more about Python.
I want to get some number total from user input then loop it and find total even and odd number. I have some line of code as below:
even = 0
odd = 0
count = float(input("Enter total point will get: "))
for i in count:
num = float(input("Type a number:"))
if num % 2 == 0:
even +=1
else:
odd +=1
print("even: ", even)
print("odd: ",odd)
But I get an exception throw TypeError: 'float' object is not iterable when I run code above.
Enter total point will get: 3
Traceback (most recent call last):
File "main.py", line 4, in <module>
for i in count:
TypeError: 'float' object is not iterable
And I am using python 3.x
Anyone can explain it to me?
How can I solve it?
Thanks for any suggestions.
Have 1 answer(s) found.
-
A0
Ana Maria Oct 19 2021
I think you need an
integernot afloatnumber. Follow solution below:Step 1: Change
float()to int() function.Change
count = float(input("Enter total point will get: "))to
count = int(input("Enter total point will get: "))Step 2: Use
range()function to hepl loop range number.Change
for i in count:to
for i in range(count):I hope it helpful for you.
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