# RuntimeWarning: Invalid value encountered in true_divide in Python

I'm a student and programming with Python is a subject in my class. It's difficult for me to start learning it. I have two arrays that need division together, division item by item. I'm using numpy `divide()`

method, like this:

` ````
import numpy as np
dividend = np.array([10, 0, 187, 58, 88, 168, 275, 77, 88, 0])
divisor = np.array([1, 2, 3, 4, 5, 6, 7, 8, 9, 0])
print(np.divide(dividend, divisor))
```

When I was running the code above it's not throw any exceptions but had a warning show **RuntimeWarning: Invalid value encountered in true_divide**.

` ````
[10. 0. 62.33333333 14.5 17.6 28. 39.28571429 9.625 9.77777778 nan]
main.py:6: RuntimeWarning: invalid value encountered in true_divide
print(np.divide(dividend, divisor))
```

It's difficult to understand, anyone can explain it to help me?

Thanks in advance.

**1**answer(s) found.

- M0
Mary Christ May 07 2022

The NumPy

`divide()`

method will return the quotient value after the division. Hence in our case following division takes place.- 10/1 = 10 (good, valid format)
- 0/2 = 0 (good, valid format)
- 187/3 = 62.3 (good, valid format)
- 58/4 = 14.5 (good, valid format)
- 88/5 = 17.6 (good, valid format)
- 168/6 = 28 (good, valid format)
- 275/7 = 39.2 (good, valid format)
- 77/8 = 9.6 (good, valid format)
- 88/9 = 9.7 (good, valid format)
- 0/0 = infinity (This would be treated as an invalid operation as 0 divisible by 0 would lead to nan; hence we get the warning)

So

**how to fix RuntimeWarning: invalid value encountered in true_divide**?`Solution 1`

: Ignore the invalid warning message by using`seterr()`

method of`numpy`

`import numpy as np dividend = np.array([10, 0, 187, 58, 88, 168, 275, 77, 88, 0]) divisor = np.array([1, 2, 3, 4, 5, 6, 7, 8, 9, 0]) np.seterr(invalid='ignore') # Add more this line print(np.divide(dividend, divisor))`

`Solution 2`

: remove any item 0/0 in two array.I hope this explanation will helpful for you.

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