IndexError: index 1 is out of bounds for axis 0 with size 1
Dung Do Tien
Mar 26 2022
657
Hello Guys, I'm just studying Python two days before and I practiced with the array using NumPy package.
I have created an array of 3 dimensions and I want to get some items on it. Like this
# Import the numpy library
import numpy as np
# Declaring and Initializing the block 3D Dimension Array
blocks = np.array([[[10,1],[20,2],[30,3],[40,4],[50,5]]])
#print first block here
print(blocks[1][1])
But when running the code above I got an error IndexError: index 1 is out of bounds for axis 0 with size 1. I feel this block code is very basic but I don't understand this error.
Traceback (most recent call last):
File "HelloWorld.py", line 8, in <module>
print(blocks[1][1])
IndexError: index 1 is out of bounds for axis 0 with size 1
I'm using Python 3.9.9 and running on Windows 11 64bit.
Do you have any suggestions for me?
Thank you so much.
Have 1 answer(s) found.
-
m-15
mohammad faizan Mar 26 2022
Oh, I think you still don't know a theory very basic about an array, that is the index of an array is always from 0, not 1.
[[[10,1],[20,2],[30,3],[40,4],[50,5]]]You can see, your array has 3 dimensions and has only one item. So you have to access from 0. You can see the demo below:
print(blocks[0][1]) # Print [20 2] print(blocks[0][1][0]) # Print 20 print(blocks[0][0][1]) # Print 1 print(blocks[0]) # Print [[10,1],[20,2],[30,3],[40,4],[50,5]]I hope, this answer is useful to you.
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